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3x=6/2x-3
We move all terms to the left:
3x-(6/2x-3)=0
Domain of the equation: 2x-3)!=0We get rid of parentheses
x∈R
3x-6/2x+3=0
We multiply all the terms by the denominator
3x*2x+3*2x-6=0
Wy multiply elements
6x^2+6x-6=0
a = 6; b = 6; c = -6;
Δ = b2-4ac
Δ = 62-4·6·(-6)
Δ = 180
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{180}=\sqrt{36*5}=\sqrt{36}*\sqrt{5}=6\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6\sqrt{5}}{2*6}=\frac{-6-6\sqrt{5}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6\sqrt{5}}{2*6}=\frac{-6+6\sqrt{5}}{12} $
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