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3x=6x(x-5)
We move all terms to the left:
3x-(6x(x-5))=0
We calculate terms in parentheses: -(6x(x-5)), so:We get rid of parentheses
6x(x-5)
We multiply parentheses
6x^2-30x
Back to the equation:
-(6x^2-30x)
-6x^2+3x+30x=0
We add all the numbers together, and all the variables
-6x^2+33x=0
a = -6; b = 33; c = 0;
Δ = b2-4ac
Δ = 332-4·(-6)·0
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1089}=33$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-33}{2*-6}=\frac{-66}{-12} =5+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+33}{2*-6}=\frac{0}{-12} =0 $
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