3x=8-2(1-x)=1

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Solution for 3x=8-2(1-x)=1 equation: 



3x=8-2(1-x)=1

We move all terms to the left:

3x-(8-2(1-x))=0

We add all the numbers together, and all the variables

3x-(8-2(-1x+1))=0



We calculate terms in parentheses: -(8-2(-1x+1)), so:

8-2(-1x+1)

determiningTheFunctionDomain
-2(-1x+1)+8

We multiply parentheses

2x-2+8

We add all the numbers together, and all the variables

2x+6

Back to the equation:

-(2x+6)



We get rid of parentheses

3x-2x-6=0

We add all the numbers together, and all the variables

x-6=0

We move all terms containing x to the left, all other terms to the right

x=6

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