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3x=9(x+1)-3
We move all terms to the left:
3x-(9(x+1)-3)=0
We calculate terms in parentheses: -(9(x+1)-3), so:We get rid of parentheses
9(x+1)-3
We multiply parentheses
9x+9-3
We add all the numbers together, and all the variables
9x+6
Back to the equation:
-(9x+6)
3x-9x-6=0
We add all the numbers together, and all the variables
-6x-6=0
We move all terms containing x to the left, all other terms to the right
-6x=6
x=6/-6
x=-1
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