3x=92-(x+12)

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Solution for 3x=92-(x+12) equation: 



3x=92-(x+12)

We move all terms to the left:

3x-(92-(x+12))=0



We calculate terms in parentheses: -(92-(x+12)), so:

92-(x+12)

determiningTheFunctionDomain
-(x+12)+92

We get rid of parentheses

-x-12+92

We add all the numbers together, and all the variables

-1x+80

Back to the equation:

-(-1x+80)



We get rid of parentheses

3x+1x-80=0

We add all the numbers together, and all the variables

4x-80=0

We move all terms containing x to the left, all other terms to the right

4x=80

x=80/4

x=20

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