3y(1+2)=12(2y+1)

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Solution for 3y(1+2)=12(2y+1) equation: 



3y(1+2)=12(2y+1)

We move all terms to the left:

3y(1+2)-(12(2y+1))=0

We add all the numbers together, and all the variables

3y3-(12(2y+1))=0

We add all the numbers together, and all the variables

3y^3-(12(2y+1))=0



We calculate terms in parentheses: -(12(2y+1)), so:

12(2y+1)

We multiply parentheses

24y+12

Back to the equation:

-(24y+12)



We do not support eypression: y^3

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