3y(2+y)=y(3y-2)-24

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Solution for 3y(2+y)=y(3y-2)-24 equation: 


Simplifying
3y(2 + y) = y(3y + -2) + -24
(2 * 3y + y * 3y) = y(3y + -2) + -24
(6y + 3y2) = y(3y + -2) + -24

Reorder the terms:
6y + 3y2 = y(-2 + 3y) + -24
6y + 3y2 = (-2 * y + 3y * y) + -24
6y + 3y2 = (-2y + 3y2) + -24

Reorder the terms:
6y + 3y2 = -24 + -2y + 3y2

Add '-3y2' to each side of the equation.
6y + 3y2 + -3y2 = -24 + -2y + 3y2 + -3y2

Combine like terms: 3y2 + -3y2 = 0
6y + 0 = -24 + -2y + 3y2 + -3y2
6y = -24 + -2y + 3y2 + -3y2

Combine like terms: 3y2 + -3y2 = 0
6y = -24 + -2y + 0
6y = -24 + -2y

Solving
6y = -24 + -2y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '2y' to each side of the equation.
6y + 2y = -24 + -2y + 2y

Combine like terms: 6y + 2y = 8y
8y = -24 + -2y + 2y

Combine like terms: -2y + 2y = 0
8y = -24 + 0
8y = -24

Divide each side by '8'.
y = -3

Simplifying
y = -3

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