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3y(2y+3)-4y=-3
We move all terms to the left:
3y(2y+3)-4y-(-3)=0
We add all the numbers together, and all the variables
-4y+3y(2y+3)+3=0
We multiply parentheses
6y^2-4y+9y+3=0
We add all the numbers together, and all the variables
6y^2+5y+3=0
a = 6; b = 5; c = +3;
Δ = b2-4ac
Δ = 52-4·6·3
Δ = -47
Delta is less than zero, so there is no solution for the equation
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