3y(5y-1)=0

Solution for 3y(5y-1)=0 equation:

3y(5y-1)=0

We multiply parentheses

15y^2-3y=0

a = 15; b = -3; c = 0;
Δ = b2-4ac
Δ = -32-4·15·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-3}{2*15}=\frac{0}{30}
=0
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+3}{2*15}=\frac{6}{30}
=1/5
$