3y(y+1)=3y

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Solution for 3y(y+1)=3y equation: 



3y(y+1)=3y

We move all terms to the left:

3y(y+1)-(3y)=0

We add all the numbers together, and all the variables

-3y+3y(y+1)=0

We multiply parentheses

3y^2-3y+3y=0

We add all the numbers together, and all the variables

3y^2=0

a = 3; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·3·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{6}=0$

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