3y(y-15)=145

Solution for 3y(y-15)=145 equation:

3y(y-15)=145

We move all terms to the left:

3y(y-15)-(145)=0

We multiply parentheses

3y^2-45y-145=0

a = 3; b = -45; c = -145;
Δ = b2-4ac
Δ = -452-4·3·(-145)
Δ = 3765
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-\sqrt{3765}}{2*3}=\frac{45-\sqrt{3765}}{6}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+\sqrt{3765}}{2*3}=\frac{45+\sqrt{3765}}{6}
$