3y(y-2)-2y(y-3)=4

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Solution for 3y(y-2)-2y(y-3)=4 equation:


Simplifying
3y(y + -2) + -2y(y + -3) = 4

Reorder the terms:
3y(-2 + y) + -2y(y + -3) = 4
(-2 * 3y + y * 3y) + -2y(y + -3) = 4
(-6y + 3y2) + -2y(y + -3) = 4

Reorder the terms:
-6y + 3y2 + -2y(-3 + y) = 4
-6y + 3y2 + (-3 * -2y + y * -2y) = 4
-6y + 3y2 + (6y + -2y2) = 4

Reorder the terms:
-6y + 6y + 3y2 + -2y2 = 4

Combine like terms: -6y + 6y = 0
0 + 3y2 + -2y2 = 4
3y2 + -2y2 = 4

Combine like terms: 3y2 + -2y2 = 1y2
1y2 = 4

Solving
1y2 = 4

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Divide each side by '1'.
y2 = 4

Simplifying
y2 = 4

Take the square root of each side:
y = {-2, 2}

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