3y(y-5)+2=5

Solution for 3y(y-5)+2=5 equation:

3y(y-5)+2=5

We move all terms to the left:

3y(y-5)+2-(5)=0

We add all the numbers together, and all the variables

3y(y-5)-3=0

We multiply parentheses

3y^2-15y-3=0

a = 3; b = -15; c = -3;
Δ = b2-4ac
Δ = -152-4·3·(-3)
Δ = 261
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{261}=\sqrt{9*29}=\sqrt{9}*\sqrt{29}=3\sqrt{29}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-3\sqrt{29}}{2*3}=\frac{15-3\sqrt{29}}{6}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+3\sqrt{29}}{2*3}=\frac{15+3\sqrt{29}}{6}
$