3y+((182-3y)-2)=180

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Solution for 3y+((182-3y)-2)=180 equation: 



3y+((182-3y)-2)=180

We move all terms to the left:

3y+((182-3y)-2)-(180)=0

We add all the numbers together, and all the variables

3y+((-3y+182)-2)-180=0



We calculate terms in parentheses: +((-3y+182)-2), so:

(-3y+182)-2

We get rid of parentheses

-3y+182-2

We add all the numbers together, and all the variables

-3y+180

Back to the equation:

+(-3y+180)



We get rid of parentheses

3y-3y+180-180=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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