3y+(1/4)y=26

Solution for 3y+(1/4)y=26 equation:

3y+(1/4)y=26

We move all terms to the left:

3y+(1/4)y-(26)=0


Domain of the equation: 4)y!=0

y!=0/1

y!=0

y∈R


We add all the numbers together, and all the variables

3y+(+1/4)y-26=0

We multiply parentheses

y^2+3y-26=0

a = 1; b = 3; c = -26;
Δ = b2-4ac
Δ = 32-4·1·(-26)
Δ = 113
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{113}}{2*1}=\frac{-3-\sqrt{113}}{2}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{113}}{2*1}=\frac{-3+\sqrt{113}}{2}
$