3y+(2y-5)=13-2(y+2)

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Solution for 3y+(2y-5)=13-2(y+2) equation:


Simplifying
3y + (2y + -5) = 13 + -2(y + 2)

Reorder the terms:
3y + (-5 + 2y) = 13 + -2(y + 2)

Remove parenthesis around (-5 + 2y)
3y + -5 + 2y = 13 + -2(y + 2)

Reorder the terms:
-5 + 3y + 2y = 13 + -2(y + 2)

Combine like terms: 3y + 2y = 5y
-5 + 5y = 13 + -2(y + 2)

Reorder the terms:
-5 + 5y = 13 + -2(2 + y)
-5 + 5y = 13 + (2 * -2 + y * -2)
-5 + 5y = 13 + (-4 + -2y)

Combine like terms: 13 + -4 = 9
-5 + 5y = 9 + -2y

Solving
-5 + 5y = 9 + -2y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '2y' to each side of the equation.
-5 + 5y + 2y = 9 + -2y + 2y

Combine like terms: 5y + 2y = 7y
-5 + 7y = 9 + -2y + 2y

Combine like terms: -2y + 2y = 0
-5 + 7y = 9 + 0
-5 + 7y = 9

Add '5' to each side of the equation.
-5 + 5 + 7y = 9 + 5

Combine like terms: -5 + 5 = 0
0 + 7y = 9 + 5
7y = 9 + 5

Combine like terms: 9 + 5 = 14
7y = 14

Divide each side by '7'.
y = 2

Simplifying
y = 2

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