3y+(3y-4)=7y-3(y-10)

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Solution for 3y+(3y-4)=7y-3(y-10) equation:


Simplifying
3y + (3y + -4) = 7y + -3(y + -10)

Reorder the terms:
3y + (-4 + 3y) = 7y + -3(y + -10)

Remove parenthesis around (-4 + 3y)
3y + -4 + 3y = 7y + -3(y + -10)

Reorder the terms:
-4 + 3y + 3y = 7y + -3(y + -10)

Combine like terms: 3y + 3y = 6y
-4 + 6y = 7y + -3(y + -10)

Reorder the terms:
-4 + 6y = 7y + -3(-10 + y)
-4 + 6y = 7y + (-10 * -3 + y * -3)
-4 + 6y = 7y + (30 + -3y)

Reorder the terms:
-4 + 6y = 30 + 7y + -3y

Combine like terms: 7y + -3y = 4y
-4 + 6y = 30 + 4y

Solving
-4 + 6y = 30 + 4y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-4y' to each side of the equation.
-4 + 6y + -4y = 30 + 4y + -4y

Combine like terms: 6y + -4y = 2y
-4 + 2y = 30 + 4y + -4y

Combine like terms: 4y + -4y = 0
-4 + 2y = 30 + 0
-4 + 2y = 30

Add '4' to each side of the equation.
-4 + 4 + 2y = 30 + 4

Combine like terms: -4 + 4 = 0
0 + 2y = 30 + 4
2y = 30 + 4

Combine like terms: 30 + 4 = 34
2y = 34

Divide each side by '2'.
y = 17

Simplifying
y = 17

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