3y+(4y+7)=(3y+4y)+7

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Solution for 3y+(4y+7)=(3y+4y)+7 equation: 


Simplifying
3y + (4y + 7) = (3y + 4y) + 7

Reorder the terms:
3y + (7 + 4y) = (3y + 4y) + 7

Remove parenthesis around (7 + 4y)
3y + 7 + 4y = (3y + 4y) + 7

Reorder the terms:
7 + 3y + 4y = (3y + 4y) + 7

Combine like terms: 3y + 4y = 7y
7 + 7y = (3y + 4y) + 7

Combine like terms: 3y + 4y = 7y
7 + 7y = (7y) + 7
7 + 7y = (7y) + 7

Reorder the terms:
7 + 7y = 7 + (7y)

Add '-7' to each side of the equation.
7 + -7 + 7y = 7 + -7 + (7y)

Combine like terms: 7 + -7 = 0
0 + 7y = 7 + -7 + (7y)
7y = 7 + -7 + (7y)

Combine like terms: 7 + -7 = 0
7y = 0 + (7y)
7y = (7y)

Add '-7y' to each side of the equation.
7y + -7y = (7y) + -7y

Combine like terms: 7y + -7y = 0
0 = (7y) + -7y

Combine like terms: (7y) + -7y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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