3y+(4y-40)=180

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Solution for 3y+(4y-40)=180 equation:



3y+(4y-40)=180
We move all terms to the left:
3y+(4y-40)-(180)=0
We get rid of parentheses
3y+4y-40-180=0
We add all the numbers together, and all the variables
7y-220=0
We move all terms containing y to the left, all other terms to the right
7y=220
y=220/7
y=31+3/7

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