3y+(y+10)=200

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Solution for 3y+(y+10)=200 equation: 



3y+(y+10)=200

We move all terms to the left:

3y+(y+10)-(200)=0

We get rid of parentheses

3y+y+10-200=0

We add all the numbers together, and all the variables

4y-190=0

We move all terms containing y to the left, all other terms to the right

4y=190

y=190/4

y=47+1/2

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