3y+-4(3y+-4)+3=32

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Solution for 3y+-4(3y+-4)+3=32 equation: 



3y+-4(3y+-4)+3=32

We move all terms to the left:

3y+-4(3y+-4)+3-(32)=0

determiningTheFunctionDomain
3y-4(3y+-4)+3-32+=0

We add all the numbers together, and all the variables

3y-4(3y-4)+3-32+=0

We add all the numbers together, and all the variables

3y-4(3y-4)=0

We multiply parentheses

3y-12y+16=0

We add all the numbers together, and all the variables

-9y+16=0

We move all terms containing y to the left, all other terms to the right

-9y=-16

y=-16/-9

y=1+7/9

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