3y+1-(5y-4)=y-1

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Solution for 3y+1-(5y-4)=y-1 equation:


Simplifying
3y + 1 + -1(5y + -4) = y + -1

Reorder the terms:
3y + 1 + -1(-4 + 5y) = y + -1
3y + 1 + (-4 * -1 + 5y * -1) = y + -1
3y + 1 + (4 + -5y) = y + -1

Reorder the terms:
1 + 4 + 3y + -5y = y + -1

Combine like terms: 1 + 4 = 5
5 + 3y + -5y = y + -1

Combine like terms: 3y + -5y = -2y
5 + -2y = y + -1

Reorder the terms:
5 + -2y = -1 + y

Solving
5 + -2y = -1 + y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-1y' to each side of the equation.
5 + -2y + -1y = -1 + y + -1y

Combine like terms: -2y + -1y = -3y
5 + -3y = -1 + y + -1y

Combine like terms: y + -1y = 0
5 + -3y = -1 + 0
5 + -3y = -1

Add '-5' to each side of the equation.
5 + -5 + -3y = -1 + -5

Combine like terms: 5 + -5 = 0
0 + -3y = -1 + -5
-3y = -1 + -5

Combine like terms: -1 + -5 = -6
-3y = -6

Divide each side by '-3'.
y = 2

Simplifying
y = 2

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