3y+1/4y=26

Solution for 3y+1/4y=26 equation:

3y+1/4y=26

We move all terms to the left:

3y+1/4y-(26)=0


Domain of the equation: 4y!=0

y!=0/4

y!=0

y∈R


We multiply all the terms by the denominator


3y*4y-26*4y+1=0

Wy multiply elements

12y^2-104y+1=0

a = 12; b = -104; c = +1;
Δ = b2-4ac
Δ = -1042-4·12·1
Δ = 10768
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{10768}=\sqrt{16*673}=\sqrt{16}*\sqrt{673}=4\sqrt{673}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-104)-4\sqrt{673}}{2*12}=\frac{104-4\sqrt{673}}{24}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-104)+4\sqrt{673}}{2*12}=\frac{104+4\sqrt{673}}{24}
$