3y+12+10+(y+2)+(2y+1)=67

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Solution for 3y+12+10+(y+2)+(2y+1)=67 equation: 



3y+12+10+(y+2)+(2y+1)=67

We move all terms to the left:

3y+12+10+(y+2)+(2y+1)-(67)=0

We add all the numbers together, and all the variables

3y+(y+2)+(2y+1)-45=0

We get rid of parentheses

3y+y+2y+2+1-45=0

We add all the numbers together, and all the variables

6y-42=0

We move all terms containing y to the left, all other terms to the right

6y=42

y=42/6

y=7

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