3y+12=y-4

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Solution for 3y+12=y-4 equation: 



3y+12=y-4

We move all terms to the left:

3y+12-(y-4)=0

We get rid of parentheses

3y-y+4+12=0

We add all the numbers together, and all the variables

2y+16=0

We move all terms containing y to the left, all other terms to the right

2y=-16

y=-16/2

y=-8

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