3y+13=3(y-4)

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Solution for 3y+13=3(y-4) equation: 



3y+13=3(y-4)

We move all terms to the left:

3y+13-(3(y-4))=0



We calculate terms in parentheses: -(3(y-4)), so:

3(y-4)

We multiply parentheses

3y-12

Back to the equation:

-(3y-12)



We get rid of parentheses

3y-3y+12+13=0

We add all the numbers together, and all the variables

25!=0

There is no solution for this equation

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