3y+14y2-6y2-9y+1-y-3y=

Solution for 3y+14y2-6y2-9y+1-y-3y= equation:

3y+14y^2-6y^2-9y+1-y-3y=

We move all terms to the left:

3y+14y^2-6y^2-9y+1-y-3y-()=0

We add all the numbers together, and all the variables

8y^2-10y=0

a = 8; b = -10; c = 0;
Δ = b2-4ac
Δ = -102-4·8·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-10}{2*8}=\frac{0}{16}
=0
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+10}{2*8}=\frac{20}{16}
=1+1/4
$