3y+18=13y-12

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Solution for 3y+18=13y-12 equation: 



3y+18=13y-12

We move all terms to the left:

3y+18-(13y-12)=0

We get rid of parentheses

3y-13y+12+18=0

We add all the numbers together, and all the variables

-10y+30=0

We move all terms containing y to the left, all other terms to the right

-10y=-30

y=-30/-10

y=+3

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