3y+18=16-y

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Solution for 3y+18=16-y equation: 



3y+18=16-y

We move all terms to the left:

3y+18-(16-y)=0

We add all the numbers together, and all the variables

3y-(-1y+16)+18=0

We get rid of parentheses

3y+1y-16+18=0

We add all the numbers together, and all the variables

4y+2=0

We move all terms containing y to the left, all other terms to the right

4y=-2

y=-2/4

y=-1/2

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