3y+1=(2y-3)2

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Solution for 3y+1=(2y-3)2 equation:


Simplifying
3y + 1 = (2y + -3) * 2

Reorder the terms:
1 + 3y = (2y + -3) * 2

Reorder the terms:
1 + 3y = (-3 + 2y) * 2

Reorder the terms for easier multiplication:
1 + 3y = 2(-3 + 2y)
1 + 3y = (-3 * 2 + 2y * 2)
1 + 3y = (-6 + 4y)

Solving
1 + 3y = -6 + 4y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-4y' to each side of the equation.
1 + 3y + -4y = -6 + 4y + -4y

Combine like terms: 3y + -4y = -1y
1 + -1y = -6 + 4y + -4y

Combine like terms: 4y + -4y = 0
1 + -1y = -6 + 0
1 + -1y = -6

Add '-1' to each side of the equation.
1 + -1 + -1y = -6 + -1

Combine like terms: 1 + -1 = 0
0 + -1y = -6 + -1
-1y = -6 + -1

Combine like terms: -6 + -1 = -7
-1y = -7

Divide each side by '-1'.
y = 7

Simplifying
y = 7

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