3y+1=3(3y-3)-y

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Solution for 3y+1=3(3y-3)-y equation: 



3y+1=3(3y-3)-y

We move all terms to the left:

3y+1-(3(3y-3)-y)=0



We calculate terms in parentheses: -(3(3y-3)-y), so:

3(3y-3)-y

We add all the numbers together, and all the variables

-1y+3(3y-3)

We multiply parentheses

-1y+9y-9

We add all the numbers together, and all the variables

8y-9

Back to the equation:

-(8y-9)



We get rid of parentheses

3y-8y+9+1=0

We add all the numbers together, and all the variables

-5y+10=0

We move all terms containing y to the left, all other terms to the right

-5y=-10

y=-10/-5

y=+2

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