3y+2(2y-8)+20=46

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Solution for 3y+2(2y-8)+20=46 equation: 



3y+2(2y-8)+20=46

We move all terms to the left:

3y+2(2y-8)+20-(46)=0

We add all the numbers together, and all the variables

3y+2(2y-8)-26=0

We multiply parentheses

3y+4y-16-26=0

We add all the numbers together, and all the variables

7y-42=0

We move all terms containing y to the left, all other terms to the right

7y=42

y=42/7

y=6

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