3y+2(4y+11)=4(y-11)+7y

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Solution for 3y+2(4y+11)=4(y-11)+7y equation: 



3y+2(4y+11)=4(y-11)+7y

We move all terms to the left:

3y+2(4y+11)-(4(y-11)+7y)=0

We multiply parentheses

3y+8y-(4(y-11)+7y)+22=0



We calculate terms in parentheses: -(4(y-11)+7y), so:

4(y-11)+7y

We add all the numbers together, and all the variables

7y+4(y-11)

We multiply parentheses

7y+4y-44

We add all the numbers together, and all the variables

11y-44

Back to the equation:

-(11y-44)



We add all the numbers together, and all the variables

11y-(11y-44)+22=0

We get rid of parentheses

11y-11y+44+22=0

We add all the numbers together, and all the variables

66!=0

There is no solution for this equation

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