3y+2(4y-8)=6-(4y+3)+3

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Solution for 3y+2(4y-8)=6-(4y+3)+3 equation: 



3y+2(4y-8)=6-(4y+3)+3

We move all terms to the left:

3y+2(4y-8)-(6-(4y+3)+3)=0

We multiply parentheses

3y+8y-(6-(4y+3)+3)-16=0



We calculate terms in parentheses: -(6-(4y+3)+3), so:

6-(4y+3)+3

determiningTheFunctionDomain
-(4y+3)+6+3

We add all the numbers together, and all the variables

-(4y+3)+9

We get rid of parentheses

-4y-3+9

We add all the numbers together, and all the variables

-4y+6

Back to the equation:

-(-4y+6)



We add all the numbers together, and all the variables

11y-(-4y+6)-16=0

We get rid of parentheses

11y+4y-6-16=0

We add all the numbers together, and all the variables

15y-22=0

We move all terms containing y to the left, all other terms to the right

15y=22

y=22/15

y=1+7/15

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