3y+2(y+1)=4y+5

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Solution for 3y+2(y+1)=4y+5 equation: 



3y+2(y+1)=4y+5

We move all terms to the left:

3y+2(y+1)-(4y+5)=0

We multiply parentheses

3y+2y-(4y+5)+2=0

We get rid of parentheses

3y+2y-4y-5+2=0

We add all the numbers together, and all the variables

y-3=0

We move all terms containing y to the left, all other terms to the right

y=3

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