3y+2(y+2)=12-(2y-5)

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Solution for 3y+2(y+2)=12-(2y-5) equation: 



3y+2(y+2)=12-(2y-5)

We move all terms to the left:

3y+2(y+2)-(12-(2y-5))=0

We multiply parentheses

3y+2y-(12-(2y-5))+4=0



We calculate terms in parentheses: -(12-(2y-5)), so:

12-(2y-5)

determiningTheFunctionDomain
-(2y-5)+12

We get rid of parentheses

-2y+5+12

We add all the numbers together, and all the variables

-2y+17

Back to the equation:

-(-2y+17)



We add all the numbers together, and all the variables

5y-(-2y+17)+4=0

We get rid of parentheses

5y+2y-17+4=0

We add all the numbers together, and all the variables

7y-13=0

We move all terms containing y to the left, all other terms to the right

7y=13

y=13/7

y=1+6/7

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