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3y+2(y+2)=13-(2y+5)
We move all terms to the left:
3y+2(y+2)-(13-(2y+5))=0
We multiply parentheses
3y+2y-(13-(2y+5))+4=0
We calculate terms in parentheses: -(13-(2y+5)), so:We add all the numbers together, and all the variables
13-(2y+5)
determiningTheFunctionDomain -(2y+5)+13
We get rid of parentheses
-2y-5+13
We add all the numbers together, and all the variables
-2y+8
Back to the equation:
-(-2y+8)
5y-(-2y+8)+4=0
We get rid of parentheses
5y+2y-8+4=0
We add all the numbers together, and all the variables
7y-4=0
We move all terms containing y to the left, all other terms to the right
7y=4
y=4/7
y=4/7
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