3y+2(y+2)=13-(2y-5)

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Solution for 3y+2(y+2)=13-(2y-5) equation:


Simplifying
3y + 2(y + 2) = 13 + -1(2y + -5)

Reorder the terms:
3y + 2(2 + y) = 13 + -1(2y + -5)
3y + (2 * 2 + y * 2) = 13 + -1(2y + -5)
3y + (4 + 2y) = 13 + -1(2y + -5)

Reorder the terms:
4 + 3y + 2y = 13 + -1(2y + -5)

Combine like terms: 3y + 2y = 5y
4 + 5y = 13 + -1(2y + -5)

Reorder the terms:
4 + 5y = 13 + -1(-5 + 2y)
4 + 5y = 13 + (-5 * -1 + 2y * -1)
4 + 5y = 13 + (5 + -2y)

Combine like terms: 13 + 5 = 18
4 + 5y = 18 + -2y

Solving
4 + 5y = 18 + -2y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '2y' to each side of the equation.
4 + 5y + 2y = 18 + -2y + 2y

Combine like terms: 5y + 2y = 7y
4 + 7y = 18 + -2y + 2y

Combine like terms: -2y + 2y = 0
4 + 7y = 18 + 0
4 + 7y = 18

Add '-4' to each side of the equation.
4 + -4 + 7y = 18 + -4

Combine like terms: 4 + -4 = 0
0 + 7y = 18 + -4
7y = 18 + -4

Combine like terms: 18 + -4 = 14
7y = 14

Divide each side by '7'.
y = 2

Simplifying
y = 2

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