3y+2(y-2)=3y/2+1

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Solution for 3y+2(y-2)=3y/2+1 equation:



3y+2(y-2)=3y/2+1
We move all terms to the left:
3y+2(y-2)-(3y/2+1)=0
We multiply parentheses
3y+2y-(3y/2+1)-4=0
We get rid of parentheses
3y+2y-3y/2-1-4=0
We multiply all the terms by the denominator
3y*2+2y*2-3y-1*2-4*2=0
We add all the numbers together, and all the variables
-3y+3y*2+2y*2-10=0
Wy multiply elements
-3y+6y+4y-10=0
We add all the numbers together, and all the variables
7y-10=0
We move all terms containing y to the left, all other terms to the right
7y=10
y=10/7
y=1+3/7

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