3y+2(y-3)=-41

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Solution for 3y+2(y-3)=-41 equation: 



3y+2(y-3)=-41

We move all terms to the left:

3y+2(y-3)-(-41)=0

We add all the numbers together, and all the variables

3y+2(y-3)+41=0

We multiply parentheses

3y+2y-6+41=0

We add all the numbers together, and all the variables

5y+35=0

We move all terms containing y to the left, all other terms to the right

5y=-35

y=-35/5

y=-7

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