3y+2(y-3)=4(y-3)

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Solution for 3y+2(y-3)=4(y-3) equation:


Simplifying
3y + 2(y + -3) = 4(y + -3)

Reorder the terms:
3y + 2(-3 + y) = 4(y + -3)
3y + (-3 * 2 + y * 2) = 4(y + -3)
3y + (-6 + 2y) = 4(y + -3)

Reorder the terms:
-6 + 3y + 2y = 4(y + -3)

Combine like terms: 3y + 2y = 5y
-6 + 5y = 4(y + -3)

Reorder the terms:
-6 + 5y = 4(-3 + y)
-6 + 5y = (-3 * 4 + y * 4)
-6 + 5y = (-12 + 4y)

Solving
-6 + 5y = -12 + 4y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-4y' to each side of the equation.
-6 + 5y + -4y = -12 + 4y + -4y

Combine like terms: 5y + -4y = 1y
-6 + 1y = -12 + 4y + -4y

Combine like terms: 4y + -4y = 0
-6 + 1y = -12 + 0
-6 + 1y = -12

Add '6' to each side of the equation.
-6 + 6 + 1y = -12 + 6

Combine like terms: -6 + 6 = 0
0 + 1y = -12 + 6
1y = -12 + 6

Combine like terms: -12 + 6 = -6
1y = -6

Divide each side by '1'.
y = -6

Simplifying
y = -6

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