3y+2(y-4)=12

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Solution for 3y+2(y-4)=12 equation: 



3y+2(y-4)=12

We move all terms to the left:

3y+2(y-4)-(12)=0

We multiply parentheses

3y+2y-8-12=0

We add all the numbers together, and all the variables

5y-20=0

We move all terms containing y to the left, all other terms to the right

5y=20

y=20/5

y=4

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