3y+2(y-5)=35

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Solution for 3y+2(y-5)=35 equation: 



3y+2(y-5)=35

We move all terms to the left:

3y+2(y-5)-(35)=0

We multiply parentheses

3y+2y-10-35=0

We add all the numbers together, and all the variables

5y-45=0

We move all terms containing y to the left, all other terms to the right

5y=45

y=45/5

y=9

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