3y+20=3+3+2y

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Solution for 3y+20=3+3+2y equation:



3y+20=3+3+2y
We move all terms to the left:
3y+20-(3+3+2y)=0
We add all the numbers together, and all the variables
3y-(2y+6)+20=0
We get rid of parentheses
3y-2y-6+20=0
We add all the numbers together, and all the variables
y+14=0
We move all terms containing y to the left, all other terms to the right
y=-14

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