3y+20=5(y+2)

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Solution for 3y+20=5(y+2) equation: 



3y+20=5(y+2)

We move all terms to the left:

3y+20-(5(y+2))=0



We calculate terms in parentheses: -(5(y+2)), so:

5(y+2)

We multiply parentheses

5y+10

Back to the equation:

-(5y+10)



We get rid of parentheses

3y-5y-10+20=0

We add all the numbers together, and all the variables

-2y+10=0

We move all terms containing y to the left, all other terms to the right

-2y=-10

y=-10/-2

y=+5

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