3y+27=2(7y-3)

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Solution for 3y+27=2(7y-3) equation: 



3y+27=2(7y-3)

We move all terms to the left:

3y+27-(2(7y-3))=0



We calculate terms in parentheses: -(2(7y-3)), so:

2(7y-3)

We multiply parentheses

14y-6

Back to the equation:

-(14y-6)



We get rid of parentheses

3y-14y+6+27=0

We add all the numbers together, and all the variables

-11y+33=0

We move all terms containing y to the left, all other terms to the right

-11y=-33

y=-33/-11

y=+3

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