3y+28=-8(y-9)

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Solution for 3y+28=-8(y-9) equation: 



3y+28=-8(y-9)

We move all terms to the left:

3y+28-(-8(y-9))=0



We calculate terms in parentheses: -(-8(y-9)), so:

-8(y-9)

We multiply parentheses

-8y+72

Back to the equation:

-(-8y+72)



We get rid of parentheses

3y+8y-72+28=0

We add all the numbers together, and all the variables

11y-44=0

We move all terms containing y to the left, all other terms to the right

11y=44

y=44/11

y=4

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