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3y+2=(y-1)
We move all terms to the left:
3y+2-((y-1))=0
We calculate terms in parentheses: -((y-1)), so:We get rid of parentheses
(y-1)
We get rid of parentheses
y-1
Back to the equation:
-(y-1)
3y-y+1+2=0
We add all the numbers together, and all the variables
2y+3=0
We move all terms containing y to the left, all other terms to the right
2y=-3
y=-3/2
y=-1+1/2
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