3y+2x+23q-3y=40-12

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Solution for 3y+2x+23q-3y=40-12 equation:


Simplifying
3y + 2x + 23q + -3y = 40 + -12

Reorder the terms:
23q + 2x + 3y + -3y = 40 + -12

Combine like terms: 3y + -3y = 0
23q + 2x + 0 = 40 + -12
23q + 2x = 40 + -12

Combine like terms: 40 + -12 = 28
23q + 2x = 28

Solving
23q + 2x = 28

Solving for variable 'q'.

Move all terms containing q to the left, all other terms to the right.

Add '-2x' to each side of the equation.
23q + 2x + -2x = 28 + -2x

Combine like terms: 2x + -2x = 0
23q + 0 = 28 + -2x
23q = 28 + -2x

Divide each side by '23'.
q = 1.217391304 + -0.08695652174x

Simplifying
q = 1.217391304 + -0.08695652174x

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