3y+2y=y2+5+y

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Solution for 3y+2y=y2+5+y equation: 



3y+2y=y2+5+y

We move all terms to the left:

3y+2y-(y2+5+y)=0

We add all the numbers together, and all the variables

-(+y^2+y+5)+3y+2y=0

We add all the numbers together, and all the variables

-(+y^2+y+5)+5y=0

We get rid of parentheses

-y^2-y+5y-5=0

We add all the numbers together, and all the variables

-1y^2+4y-5=0

a = -1; b = 4; c = -5;
Δ = b2-4ac
Δ = 42-4·(-1)·(-5)
Δ = -4
Delta is less than zero, so there is no solution for the equation

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